area of triangle using 1/2 ab sin c

law of sines and cosines, and areas of triangles

1 area of triangle 1 area = ah h in acd = = sin c b ∴ h

b/c=1/2 =sin 3002=cos 6002a/c=√3/2 =sin 6002=

有一个重量为20 n的小物体放在斜面上,斜面底边长ab=40 cm,高bc=30 cm

[0, ] 2 a n b o 结论: sin cos ab,n ab n

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