为什么vba使用on error resume next仍然出错
以下是程序:dimswappdimpartonerrorresumenextsetswapp=getobject(,"
end subend ifexit subif err = 9 thenxxxxon error resume nextsub
为什么vba使用on error resume next仍然出错
1, 忽略错误,继续执行代码,on error resume next.
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